Gujarati
1. Electric Charges and Fields
easy

The unit of electric permittivity is

A

$Volt/m^2$

B

$Joule/coulomb$

C

$Farad/m$

D

$Henry/m$

Solution

(c) $C = \frac{{{\varepsilon _0}A}}{d}$ $⇒$ ${\varepsilon _0} = \frac{{Cd}}{A}$ $⇒$ ${\varepsilon _0}$ $⇒$ $\frac{{Farad \times m}}{{{m^2}}} \to \frac{F}{m}$

Standard 12
Physics

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