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1. Electric Charges and Fields
easy
The unit of electric permittivity is
A
$Volt/m^2$
B
$Joule/coulomb$
C
$Farad/m$
D
$Henry/m$
Solution
(c) $C = \frac{{{\varepsilon _0}A}}{d}$ $⇒$ ${\varepsilon _0} = \frac{{Cd}}{A}$ $⇒$ ${\varepsilon _0}$ $⇒$ $\frac{{Farad \times m}}{{{m^2}}} \to \frac{F}{m}$
Standard 12
Physics
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