The unit of thermal conductivity is

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Question

$\frac{\mathrm{dQ}}{\mathrm{dt}}=-(\mathrm{K}) \mathrm{A} \frac{\mathrm{dT}}{\mathrm{dx}}$

$\frac{\mathrm{J}}{\mathrm{s}}=(\mathrm{K}) \mathrm{m}^{

Vedclass · Accepted Answer

$\mathrm{Wm}^{-1} \mathrm{K}^{-1}$

Vedclass · Answer

$\frac{\mathrm{dQ}}{\mathrm{dt}}=-(\mathrm{K}) \mathrm{A} \frac{\mathrm{dT}}{\mathrm{dx}}$

$\frac{\mathrm{J}}{\mathrm{s}}=(\mathrm{K}) \mathrm{m}^{2} \frac{\mathrm{kelvin}}{\mathrm{m}}$

$(\mathrm{K})= watt \;\mathrm{m}^{-1} \mathrm{K}^{-1}$

LIST$-I$	LIST$-II$
$(A)$ Surface tension	$(I)$ $Kg m ^{-1} s ^{-1}$
$(B)$ Pressure	$(II)$ $Kg ms^{-1 }$
$(C)$ Viscosity	$(III)$ $Kg m ^{-1} s ^{-2}$
$(D)$ Impulse	$(IV)$ $Kg s ^{-2}$

Similar Questions

${\rm{Wb/}}\Omega $ unit is representing which physical quantity ?

Match List $I$ with List $II$

LIST$-I$ LIST$-II$

$(A)$ Surface tension $(I)$ $Kg m ^{-1} s ^{-1}$

$(B)$ Pressure $(II)$ $Kg ms^{-1 }$

$(C)$ Viscosity $(III)$ $Kg m ^{-1} s ^{-2}$

$(D)$ Impulse $(IV)$ $Kg s ^{-2}$

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