The value of cosec frac{pi }{{18}} - sqrt 3&n | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\frac{1}{{\sin \pi /18}}\,\, - \,\,\frac{{\sqrt 3 }}{{\cos \pi /18}}$ $=$$\frac{{2\,\left[ {\frac{1}{2}\cos \frac{\pi }{{18}}\, - \,\frac{{\sqrt 3 }}

Vedclass · Accepted Answer

natural number

Vedclass · Answer

$\frac{1}{{\sin \pi /18}}\,\, - \,\,\frac{{\sqrt 3 }}{{\cos \pi /18}}$ $=$$\frac{{2\,\left[ {\frac{1}{2}\cos \frac{\pi }{{18}}\, - \,\frac{{\sqrt 3 }}{2}\,\,\sin \frac{\pi }{{18}}} \right]}}{{\frac{{\sin \frac{\pi }{9}}}{2}}}$

$=$$\frac{{4\left[ {\sin \frac{\pi }{6}\,\,\cos \frac{\pi }{{18}}\,\, - \,\,\cos \frac{\pi }{6}\,\,\sin \frac{\pi }{{18}}} \right]}}{{\sin \frac{\pi }{9}}}$ $= 4$

The value of $cosec \frac{\pi }{{18}} - \sqrt 3 \,sec\, \frac{\pi }{{18}}$ is a

Similar Questions

The value of $\tan 81^{\circ}-\tan 63^{\circ}-\tan 27^{\circ}+\tan 9^{\circ}$ is

If $90^\circ < A < 180^\circ $ and $\sin A = \frac{4}{5},$ then $\tan \frac{A}{2}$ is equal to

If $x = sec\, \phi - tan\, \phi$ & $y = cosec\, \phi + cot\, \phi$ then :

$\tan 9^\circ - \tan 27^\circ - \tan 63^\circ + \tan 81^\circ = $

The value of $\sin \frac{\pi }{{14}}\sin \frac{{3\pi }}{{14}}\sin \frac{{5\pi }}{{14}}\sin \frac{{7\pi }}{{14}}\sin \frac{{9\pi }}{{14}}\sin \frac{{11\pi }}{{14}}\sin \frac{{13\pi }}{{14}}$ is equal to