The value of the polynomial $5 x-4 x^{2}+3,$ when $x=-1$ is
$2$
$6$
$-6$
$-2$
Let $P(x)=5 x-4 x^{2}+3$
Therefore, $P(-1)=5(-1)-4(-1)^{2}+3=-5-4+3=-6$
Hence, $(c)$ is the correct answer.
Write whether the statement are True or False. Justify your answer.
Zero of a polynomial is always $0.$
For the polynomial $p(x)=x^{2}-7 x+12$ $p(2)=\ldots \ldots . .$
Verify whether $2$ and $5$ are zeros of the polynomial $x^{2}-2 x-15$ or not.
If $x+y=-4,$ then what is the value of $x^{3}+y^{3}-12 x y+64 ?$
Check whether $g(x)$ is a factor of $p(x)$ or not, where
$p(x)=8 x^{3}-6 x^{2}-4 x+3, \quad g(x)=\frac{x}{3}-\frac{1}{4}$
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