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3-2.Motion in Plane
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The velocity and acceleration vectors of a particle undergoing circular motion are $\overrightarrow{ v }=2 \hat{ i } m / s$ and $\overrightarrow{ a }=2 \hat{ i }+4 \hat{ j } m / s ^2$ respectively at an instant of time. The radius of the circle is $........\,m$
A$1$
B$2$
C$3$
D$4$
Solution
(a)
It can be observed that component of acceleration perpendicular to velocity is a $=4 m / s ^2$
$\therefore \text { radius }=\frac{ v ^2}{ a _{ c }}=\frac{(2)^2}{4}=1 \text { metre }$
It can be observed that component of acceleration perpendicular to velocity is a $=4 m / s ^2$
$\therefore \text { radius }=\frac{ v ^2}{ a _{ c }}=\frac{(2)^2}{4}=1 \text { metre }$
Standard 11
Physics
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