3-2.Motion in Plane
medium

The velocity and acceleration vectors of a particle undergoing circular motion are $\overrightarrow{ v }=2 \hat{ i } m / s$ and $\overrightarrow{ a }=2 \hat{ i }+4 \hat{ j } m / s ^2$ respectively at an instant of time. The radius of the circle is $........\,m$

A$1$
B$2$
C$3$
D$4$

Solution

(a)
It can be observed that component of acceleration perpendicular to velocity is a $=4 m / s ^2$
$\therefore \text { radius }=\frac{ v ^2}{ a _{ c }}=\frac{(2)^2}{4}=1 \text { metre }$
Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.