Velocity of a particle moving in positive direction of x -axis varies as v=5 √{x} . Assuming that

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2.Motion in Straight Line

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The velocity of a particle moving in the positive direction of $x$-axis varies as $v=5 \sqrt{x}$. Assuming that at $t=0$, particle was at $x=0$. What is the acceleration of the particle $.........m/s^2$

A$12.5$

B$7.5$

C$5$

D$2.5$

Solution

(a)
$v^2=25 x$, comparing with $v^2=2 a s$, we have,
$a=12.5\,m / s ^2$

Standard 11

Physics

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