A body is moving with uniform acceleration de | vedclass

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(c) $\because {S_1} = ut + \frac{1}{2}a{t^2}$.....(i)

and velocity after first $t \,sec$

$v = u + at$

Now, ${S_2} = vt + \frac{1}{2}a{t^2}$

Vedclass · Accepted Answer

$5.5$

Vedclass · Answer

(c) $\because {S_1} = ut + \frac{1}{2}a{t^2}$.....(i)

and velocity after first $t \,sec$

$v = u + at$

Now, ${S_2} = vt + \frac{1}{2}a{t^2}$

$ = (u + at)t + \frac{1}{2}a{t^2}$..... (ii)

Equation (ii) -(i)

$\Rightarrow {S_2} - {S_1} = a{t^2}$

$ \Rightarrow a = \frac{{{S_2} - {S_1}}}{{{t^2}}} = \frac{{65 - 40}}{{{{(5)}^2}}} = 1\;m/{s^2}$

From equation (i), we get,

${S_1} = ut + \frac{1}{2}a{t^2}$ $ \Rightarrow 40 = 5u + \frac{1}{2} 	imes 1 	imes 25$

$ \Rightarrow 5u = 27.5$

$	herefore \;\;u = 5.5\;m/s$

A body is moving with uniform acceleration describes $40\, m$ in the first $5 \,sec$ and $65\, m$ in next $5 \,sec$. Its initial velocity will be........$m/s$

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