3-2.Motion in Plane
medium

The velocity of projection of a body is increased by $2 \% .$ Other factors remaining unchanged, what will be the percentage change in the maximum height attained ? (in $\%$)

A

$1$

B

$2$

C

$4$

D

$8$

(AIIMS-2019)

Solution

The formula for the maximum height during projectile motion is,

$h=\frac{(u \sin \theta)^{2}}{2 g}$

$h=\frac{u^{2} \sin ^{2} \theta}{2 g}$

Now,

$\frac{\Delta h}{h}=\frac{2 \Delta u}{u}$

$\frac{\Delta h}{h}=2 \times 2=4 \%$

Standard 11
Physics

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