Gujarati
14.Waves and Sound
easy

The velocity of waves in a string fixed at both ends is $2 m/s$. The string forms standing waves with nodes $5.0 cm$ apart. The frequency of vibration of the string in $Hz$ is

A

$40$

B

$30$

C

$20$

D

$10$

Solution

(c) Here $\frac{\lambda }{2} = 5.0\,cm\,\,$$ \Rightarrow \lambda = 10$$cm$
Hence $n = \frac{v}{\lambda } = \frac{{200}}{{10}} = 20\,Hz.$

Standard 11
Physics

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