1.Units, Dimensions and Measurement
medium

The vernier constant of Vernier callipers is $0.1 \,mm$ and it has zero error of $(-0.05) \,cm$. While measuring diameter of a sphere, the main scale reading is $1.7 \,cm$ and coinciding vernier division is $5$. The corrected diameter will be ........... $\times 10^{-2} \,cm$

A

$160$

B

$150$

C

$189$

D

$180$

(JEE MAIN-2022)

Solution

Measured diameter $= MSR + VSR \times VC$

$=1.7+0.01 \times 5$

$=1.75$

Corrected $=$ Measured – Error

$=1.75-(-0.05)$

$=1.80 \,cm$

$=180 \times 10^{-2} \,cm$

$180$

Standard 11
Physics

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