- Home
- Standard 11
- Physics
1.Units, Dimensions and Measurement
medium
The vernier constant of Vernier callipers is $0.1 \,mm$ and it has zero error of $(-0.05) \,cm$. While measuring diameter of a sphere, the main scale reading is $1.7 \,cm$ and coinciding vernier division is $5$. The corrected diameter will be ........... $\times 10^{-2} \,cm$
A
$160$
B
$150$
C
$189$
D
$180$
(JEE MAIN-2022)
Solution
Measured diameter $= MSR + VSR \times VC$
$=1.7+0.01 \times 5$
$=1.75$
Corrected $=$ Measured – Error
$=1.75-(-0.05)$
$=1.80 \,cm$
$=180 \times 10^{-2} \,cm$
$180$
Standard 11
Physics
Similar Questions
hard