The voltage of an $ac$ source varies with time according to the equation $V = 100\sin \,\left( {100\pi t} \right)\cos \,\left( {100\pi t} \right)$ where $t$ is in seconds and $V$ is in volts. Then
The voltage of an $ac$ source varies with time according to the equation $V = 100\sin \,\left( {100\pi t} \right)\cos \,\left( {100\pi t} \right)$ where $t$ is in seconds and $V$ is in volts. Then
- A
The peak voltage of the source is $100\,volts$
- B
The peak voltage of the source is $50\,volts$
- C
The peak voltage of the source is $100/\sqrt 2\,volts$
- D
The frequency of the source is $50\,Hz$
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- [AIIMS 2009]
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- [JEE MAIN 2019]
The peak voltage of the ac source is equal to:
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- [NEET 2022]
The $r.m.s.$ voltage of the wave form shown is
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