Volume of air increases by 5% in its adiabatic expansion. percentage decrease in its pressure will b

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11.Thermodynamics

medium

The volume of air increases by $5\%$ in its adiabatic expansion. The percentage decrease in its pressure will be ...... $\%$

$5$

$6$

$7$

$8$

Solution

(c) $P{V^\gamma } = K$or $P\gamma \,{V^{\gamma – 1}}dV + dP.\;{V^\gamma } = 0$
or $\frac{{dP}}{P} = – \gamma \frac{{dV}}{V}$ or $\frac{{dP}}{P} \times 100 = – \gamma \,\left( {\frac{{dV}}{V} \times 100} \right)$
$ = – 1.4 \times 5 = 7\% $

Standard 11

Physics

In Column$-I$ process and in Column$-II$ first law of thermodynamics are given. Match them appropriately :

Column$-I$ Column$-II$

$(a)$ Adiabatic $(i)$ $\Delta Q = \Delta U$

$(b)$ Isothermal $(ii)$ $\Delta Q = \Delta W$

$(iii)$ $\Delta U = -\Delta W$

easy

The pressure and density of a diatomic gas $(\gamma = 7/5)$ change adiabatically from $(P, d)$ to $(P', d')$. If $\frac{{d'}}{d} = 32$, then $\frac{{P'}}{P}$ should be

medium

A sample of gas at temperature $\mathrm{T}$ is adiabatically expanded to double its volume. Adiabatic constant for the gas is $\gamma=3 / 2$. The work done by the gas in the process is : $(\mu=1 \mathrm{~mole})$

hard

(JEE MAIN-2024)

The adiabatic elasticity of hydrogen gas $(\gamma = 1.4)$ at $NTP$ is

medium

$Assertion :$ Air quickly leaking out of a balloon becomes cooler.
$Reason :$ The leaking air undergoes adiabatic expansion.

easy

(AIIMS-2005)

Column$-I$	Column$-II$
$(a)$ Adiabatic	$(i)$ $\Delta Q = \Delta U$
$(b)$ Isothermal	$(ii)$ $\Delta Q = \Delta W$
	$(iii)$ $\Delta U = -\Delta W$

The volume of air increases by $5\%$ in its adiabatic expansion. The percentage decrease in its pressure will be ...... $\%$

Solution

Similar Questions

In Column$-I$ process and in Column$-II$ first law of thermodynamics are given. Match them appropriately : Column$-I$ Column$-II$ $(a)$ Adiabatic $(i)$ $\Delta Q = \Delta U$ $(b)$ Isothermal $(ii)$ $\Delta Q = \Delta W$ $(iii)$ $\Delta U = -\Delta W$

The pressure and density of a diatomic gas $(\gamma = 7/5)$ change adiabatically from $(P, d)$ to $(P', d')$. If $\frac{{d'}}{d} = 32$, then $\frac{{P'}}{P}$ should be

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$Assertion :$ Air quickly leaking out of a balloon becomes cooler. $Reason :$ The leaking air undergoes adiabatic expansion.

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In Column$-I$ process and in Column$-II$ first law of thermodynamics are given. Match them appropriately :

Column$-I$ Column$-II$

$(a)$ Adiabatic $(i)$ $\Delta Q = \Delta U$

$(b)$ Isothermal $(ii)$ $\Delta Q = \Delta W$

$(iii)$ $\Delta U = -\Delta W$

$Assertion :$ Air quickly leaking out of a balloon becomes cooler.
$Reason :$ The leaking air undergoes adiabatic expansion.