Work done in placing a charge of 8 × 10^{-18} coulomb on a condenser of capacity 100, micro-farad i

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1. Electric Charges and Fields

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The work done in placing a charge of $8 \times 10^{-18}$ coulomb on a condenser of capacity $100\, micro-farad$ is

A

$16 \times {10^{-32}}\,J$

B

$3.1 \times {10^{-26}}\,J$

C

$4 \times {10^{-10}}\,J$

D

$32 \times {10^{-32}}\,J$

Solution

$\mathrm{W} \cdot \mathrm{D}=\frac{8^{2}}{2 \mathrm{C}}=\frac{1}{2} \mathrm{CV}^{2}=\frac{8 \mathrm{V}}{2}$

$\mathrm{W.D}=\frac{1}{2} \frac{\left(8 \times 10^{-18}\right)^{2}}{100 \times 10^{-6}}=32 \times 10^{-32}$ $\mathrm{joule}.$

Standard 12

Physics

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