The work done per unit volume to stretch the length of area of cross-section $2 \,mm ^2$ by $2 \%$ will be ....... $MJ / m ^3$ $\left[Y=8 \times 10^{10} \,N / m ^2\right]$

  • A

    $40$

  • B

    $32$

  • C

    $64$

  • D

    $16$

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