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4-1.Newton's Laws of Motion
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Three blocks $A, B$ and $C$ are suspended as shown in the figure. Mass of each blocks $A$ and $C$ is $m$. If system is in equilibrium and mass of $B$ is $M$, then :
A
$M=2 m$
B
$M < 2 m$
C
$M >2 m$
D
$M=m$
Solution
$2 T \cos \theta=M g$
$2 mg \cos \theta=M g$
$\theta \text { always } > 0 \text { so } M < 2 m$
Standard 11
Physics
