Three blocks are initially placed as shown in | vedclass

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Question

since, $A$ and $B$ have same mass. So, after elastic collision, they interchange their velocity

$	herefore \mathrm{v}_{\mathrm{B}}=\mathrm{v}$

Vedclass · Accepted Answer

$0.6v$ to the left

Vedclass · Answer

since, $A$ and $B$ have same mass. So, after elastic collision, they interchange their velocity

$	herefore \mathrm{v}_{\mathrm{B}}=\mathrm{v}$

After collision between $\mathrm{B}$ and $\mathrm{C}$

$\mathrm{v}_{\mathrm{B}}=\left(\frac{\mathrm{m}-4 \mathrm{m}}{\mathrm{m}+4 \mathrm{m}}ight) \mathrm{v}+\left(\frac{2 	imes 4 \mathrm{m} 	imes 0}{\mathrm{m}+4 \mathrm{m}}ight)=-\frac{3}{5} \mathrm{v}$

Again, collision takes place between $A$ and $B .$ So, velocity will be inter changed.

$	herefore v_{A}=\left(v_{B}ight)=\frac{3}{5} v$

in left ward direction.

Three blocks are initially placed as shown in the figure. Block $A$ has mass $m$ and initial velocity $v$ to the right. Block $B$ with mass $m$ and block $C$ with mass $4m$ are both initially at rest. Neglect friction. All collisions are elastic. The final velocity of block $A$ is

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