Three bodies $A, B$ and $C$ have equal kinetic energies and their masses are $400 \mathrm{~g}, 1.2 \mathrm{~kg}$ and $1.6 \mathrm{~kg}$ respectively. The ratio of their linear momenta is :

A stationary particle breaks into two parts of masses $m_A$ and $m_B$ which move with velocities $v_A$ and $V_B$ respectively. The ratio of their kinetic energies $\left(\mathrm{K}_B: \mathrm{K}_{\mathrm{A}}\right)$ is :

If velocity of a body is twice of previous velocity, then kinetic energy will become

A block moving horizontally on a smooth surface with a speed of $40\, {ms}^{-1}$ splits into two equal parts. If one of the parts moves at $60\, {ms}^{-1}$ in the same direction, then the fractional change in the kinetic energy will be $x: 4$ where $x=..... .$

The energy required to break one bond in $DNA$ is $10^{-20}\, J.$ This value in $eV$ is nearly

A spring is compressed between two toy carts of masses $m_1$ and $m_2$. When the toy carts are released the spring exerts equal and opposite forces for the same time $t$ on each toy cart. If the coefficients of friction $\mu $ between the ground and the toy carts are equal, then the displacement of the toy carts are in the ratio