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5.Work, Energy, Power and Collision
hard
Three bodies $A, B$ and $C$ have equal kinetic energies and their masses are $400 \mathrm{~g}, 1.2 \mathrm{~kg}$ and $1.6 \mathrm{~kg}$ respectively. The ratio of their linear momenta is :
A
$1: \sqrt{3}: 2$
B
$1: \sqrt{3}: \sqrt{2}$
C
$\sqrt{2}: \sqrt{3}: 1$
D
$\sqrt{3}: \sqrt{2}: 1$
(JEE MAIN-2024)
Solution
$\mathrm{KE}=\frac{\mathrm{P}^2}{2 \mathrm{~m}}$
$\mathrm{P} \propto \sqrt{\mathrm{m}}$
$\text { Hence, } \mathrm{P}_{\mathrm{A}}: \mathrm{P}_{\mathrm{B}}: \mathrm{P}_{\mathrm{C}}$
$=\sqrt{400}: \sqrt{1200}: \sqrt{1600}=1: \sqrt{3}: 2$
Standard 11
Physics
