A body of mass 8,kg and another of mass 2, kg | vedclass

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Question

$K E=\frac{ P ^{2}}{2 m }$

$K _{1}=\frac{ P _{1}^{2}}{2(8)} ; K _{2}=\frac{ P _{2}{ }^{2}}{2(2)}$

$K _{1}= K _{2}$

So,

$4 P _{2}^{2}= P _{

Vedclass · Accepted Answer

$2:1$

Vedclass · Answer

$K E=\frac{ P ^{2}}{2 m }$

$K _{1}=\frac{ P _{1}^{2}}{2(8)} ; K _{2}=\frac{ P _{2}{ }^{2}}{2(2)}$

$K _{1}= K _{2}$

So,

$4 P _{2}^{2}= P _{1}^{2}$

$\frac{ P _{1}}{ P _{2}}=2$

A body of mass $8\,kg$ and another of mass $2\, kg$ are moving with equal kinetic energy. The ratio of their respective momenta will be.

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