A body of mass $8\,kg$ and another of mass $2\, kg$ are moving with equal kinetic energy. The ratio of their respective momenta will be.

Two identical uniform discs roll without slipping on two different surfaces $AB$ and $CD$ (see figure) starting at $A$ and $C$ with linear speeds $v _1$ and $v _2$, respectively, and always remain in contact with the surfaces. If they reach $B$ and $D$ with the same linear speed and $v_1=3 \ m / s$, then $v_2$ in $m / s$ is $\left(g=10 \ m / s ^2\right)$

At time $t=0$ is particle starts moving along the $x-$axis. If its kinetic energy increases uniformly with time $t$, the net force acting on it must be proportional to

If the momentum of a body is increased by $100\%$, then the percentage increase in the kinetic energy is ............ $\%$

The energy required to break one bond in $DNA$ is $10^{-20}\, J.$ This value in $eV$ is nearly

A body moving with velocity $v$ has momentum and kinetic energy numerically equal. What is the value of $v$ ........$m/s$