25 mu mathrm{F}, 30 mu mathrm{F} અને 45 mu ma | vedclass

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Question

In parallel combination : Potential difference is same across all

$	ext { Energy }=\frac{1}{2}\left(\mathrm{C}_1+\mathrm{C}_2+\mathrm{C}_3ight)

Vedclass · Accepted Answer

$86$

Vedclass · Answer

In parallel combination : Potential difference is same across all

$	ext { Energy }=\frac{1}{2}\left(\mathrm{C}_1+\mathrm{C}_2+\mathrm{C}_3ight) \mathrm{V}^2$

$=\frac{1}{2}(25+30+45) 	imes(100)^2 	imes 10^{-6}=0.5=\mathrm{E}$

In series combination: Charge is same on all.

$\frac{1}{\mathrm{C}_{	ext {equ }}}=\frac{1}{\mathrm{C}_1}+\frac{1}{\mathrm{C}_2}+\frac{1}{\mathrm{C}_3}=\frac{1}{25}+\frac{1}{30}+\frac{1}{45}$

$\frac{1}{\mathrm{C}_{	ext {equ }}}=\frac{(18+15+10)}{450}=\frac{43}{450} \Rightarrow \mathrm{C}_{	ext {equ }}=\frac{450}{43}$

$	ext { Energy }=\frac{Q^2}{2 C_1}+\frac{Q^2}{2 C_2}+\frac{Q^2}{2 C_3}$

$=\frac{Q^2}{2}\left[\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}ight]$

$\frac{\left(V 	imes C_{	ext {equ }}ight.}{2} 	imes \frac{1}{C_{	ext {equ }}}frac{V^2 C_{	ext {equ }}}{2}$

$\frac{(100)^2}{2} 	imes \frac{450}{} 	imes 10^{-6}$

$\Rightarrow \frac{4.5}{86}=\frac{9}{x} E=\frac{9}{x} 	imes 0.5 \Rightarrow x=86$

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