Three coins are tossed once. Find the probabi | vedclass

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Question

When three coins are tossed once, the sample space is given by $S =\{ HHH , HHT , HTH , THH , HTT , THT , TTH , TTT \}$

$	herefore$ Accordingly, $

Vedclass · Accepted Answer

$\frac{7}{8}$

Vedclass · Answer

When three coins are tossed once, the sample space is given by $S =\{ HHH , HHT , HTH , THH , HTT , THT , TTH , TTT \}$

$	herefore$ Accordingly, $n ( S )=8$

It is known that the probability of an event $A$ is given by

$P ( A )=\frac{	ext { Number of outcomes favourable to } A }{	ext { Total number of possible outcomes }}=\frac{n( A )}{n( S )}$

Let $J$ be the event of the occurrence of at most $2$ tails.

Accordingly, $J=\{H H H,\, H H T , \,H T H ,  \,T H H , \,H T T , \,T H T , \, T T H \} ~$

$	herefore P(J)=\frac{n(J)}{n(S)}=\frac{7}{8}$

Three coins are tossed once. Find the probability of getting atmost two tails.

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