Two dices are rolled. If both dices have six faces numbered 1,2,3,5,7 and 11, then probability that

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14.Probability

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Two dices are rolled. If both dices have six faces numbered $1,2,3,5,7$ and $11,$ then the probability that the sum of the numbers on the top faces is less than or equal to $8$ is

A

$\frac{4}{9}$

B

$\frac{17}{36}$

C

$\frac{5}{12}$

D

$\frac{1}{2}$

(JEE MAIN-2021)

Solution

$n ( E )=5+4+4+3+1=17$

So, $P(E)=\frac{17}{36}$

Standard 11

Mathematics

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