Gujarati
p-Block Elements - I
hard

Three moles of $B _2 H _6$ are completely reacted with methanol. The number of moles of boron containing product formed is

A

$5$

B

$6$

C

$7$

D

$8$

(IIT-2015)

Solution

$B _2 H _6+6 MeOH \longrightarrow 2 B ( OMe )_3+6 H _2$

$1$ mole of $B _2 H _6$ reacts with $6$ mole of $MeOH$ to give $2$ moles of $B ( OMe )$. $3$ mole of $B _2 H _6$ will react with $18$ mole of $MeOH$ to give $6$ moles of $B ( OMe ) 3$

Standard 11
Chemistry

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