- Home
- Standard 11
- Chemistry
p-Block Elements - I
hard
Three moles of $B _2 H _6$ are completely reacted with methanol. The number of moles of boron containing product formed is
A
$5$
B
$6$
C
$7$
D
$8$
(IIT-2015)
Solution
$B _2 H _6+6 MeOH \longrightarrow 2 B ( OMe )_3+6 H _2$
$1$ mole of $B _2 H _6$ reacts with $6$ mole of $MeOH$ to give $2$ moles of $B ( OMe )$. $3$ mole of $B _2 H _6$ will react with $18$ mole of $MeOH$ to give $6$ moles of $B ( OMe ) 3$
Standard 11
Chemistry