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Consider the following flow diagram :-
Compound $X$ and $Y$ are respectively.

$Na_2B_4O_7.10H_2O, B_2O_3$
$NaBO_2, Na_2B_4O_7.10H_2O$
$NaBO_2, CaCO_3$
$Na_2B_4O_7.10H_2O, CaCO_3$
Solution
$\mathop {2CaO.3{B_2}{O_3}}\limits_{Colemanite} + 2N{a_2}C{O_3} \to $ $2CaCO_3^ – + N{a_2}{B_4}{O_7} + 2NaB{O_2}$ $\xrightarrow{\begin{subarray}{l}
Filtered \\
– CaC{O_3}\,(as\,residue)
\end{subarray} }\underbrace {N{a_2}{B_4}{O_7} + NaB{O_2}}_{in\,solution}$ $\xleftarrow[\begin{subarray}{l}
and\,allowed\,to\, \\
crystallise\,out \\
and\,filtered
\end{subarray} ]{{Concentrated}}\mathop {N{a_2}{B_4}{O_7}.10{H_2}O}\limits_{as\,residue} $ $\mathop { + NaB{O_2}}\limits_{in\,filtrate} \xrightarrow{\begin{subarray}{l}
C{O_2}\,passed\,and \\
crystallise\,out\,again
\end{subarray} }N{a_2}{B_4}{O_7}.10{H_2}O \downarrow $
$[4NaB{O_2} + C{O_2} \to N{a_2}{B_4}{O_7} + N{a_2}C{O_3}]$