Consider the following flow diagram :-

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Question

$\mathop {2CaO.3{B_2}{O_3}}\limits_{Colemanite}  + 2N{a_2}C{O_3} 	o $ $2CaCO_3^ -  + N{a_2}{B_4}{O_7} + 2NaB{O_2}$ $\xrightarrow{

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$NaBO_2, Na_2B_4O_7.10H_2O$

Vedclass · Answer

$\mathop {2CaO.3{B_2}{O_3}}\limits_{Colemanite}  + 2N{a_2}C{O_3} 	o $ $2CaCO_3^ -  + N{a_2}{B_4}{O_7} + 2NaB{O_2}$ $\xrightarrow{\begin{subarray}{l} 
  Filtered \ 
   - CaC{O_3}\,(as\,residue) 
\end{subarray} }\underbrace {N{a_2}{B_4}{O_7} + NaB{O_2}}_{in\,solution}$ $\xleftarrow[\begin{subarray}{l} 
  and\,allowed\,to\, \ 
  crystallise\,out \ 
  and\,filtered 
\end{subarray} ]{{Concentrated}}\mathop {N{a_2}{B_4}{O_7}.10{H_2}O}\limits_{as\,residue} $ $\mathop { + NaB{O_2}}\limits_{in\,filtrate} \xrightarrow{\begin{subarray}{l} 
  C{O_2}\,passed\,and \ 
  crystallise\,out\,again 
\end{subarray} }N{a_2}{B_4}{O_7}.10{H_2}O \downarrow $

$[4NaB{O_2} + C{O_2} 	o N{a_2}{B_4}{O_7} + N{a_2}C{O_3}]$

Consider the following flow diagram :-

Compound $X$ and $Y$ are respectively.

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