Three pairs of compounds are given below. Identify that compound in each of the pairs which has group $-13$ element in more stable oxidation state. Give reason for your choice. State the nature of bonding also. $(A)$ $TlCl_3, TlCl$ $(B)$ $AlCl, AlCl$ $(C)$ $InCl_3, InCl$
$(A)$ $\mathrm{TlCl}$ is more stable than $\mathrm{TlCl}_{3}$ because moving down the group lower oxidation state is more stable due to inert pair effect.
$(B)$ $\mathrm{AlCl}_{3}$ is more stable because it does not show inert pair effect. It is a covalent compound and acts as a Lewis acid
$(C)$ $\mathrm{InCl}$ is more stable due to inert pair effect and lower oxidation state $+1$ is more stable. In shows both the oxidation states $+3$ and $+1$.
$3 \mathrm{InCl}_{\text {(aq) }} \rightarrow 2 \mathrm{In}_{\text {(s) }}+\mathrm{In}_{\text {(aq) }}^{3+}+3 \mathrm{Cl}_{\text {(aq) }}^{-}$
Which of the following is a non-metal
Which of the following is responsible for cleansing action of Borax
The stability of $+ 1$ oxidation state among $Al,Ga, In$ and $Tl$ increases in the sequence
Given below are two statements :
Statement $I$ : Boron is extremely hard indicating its high lattice energy
Statement $II$ : Boron has highest melting and boiling point compared to its other group members.
In the light of the above statements, choose the most appropriate answer from the options given below
When metal $X$ is treated with sodium hydroxide, a white precipitate $(A)$ is obtained, which is soluble in excess of $NaOH$ to give soluble complex $(B)$. Compound $(A)$ is soluble in dilute $HCl$ to form compound $(C)$. The compound $(A)$ when heated strongly gives $(D)$, which is used to extract metal. Identify $(X), (A), (B), (C)$ and $(D)$. Write suitable equations to support their identities.