Three particle A, B and C move in a circle of | vedclass

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Question

Let the particles meet at point $P$ after time $t.$

 Thus using $	heta^{\prime}=w t$ where $w=\frac{\bar{v}}{r}$

For $A:$  $	heta=\f

Vedclass · Accepted Answer

$5 : 4$

Vedclass · Answer

Let the particles meet at point $P$ after time $t.$

 Thus using $	heta^{\prime}=w t$ where $w=\frac{\bar{v}}{r}$

For $A:$  $	heta=\frac{1}{r} t$      $....(1)$

For $B:$        $	heta+\frac{\pi}{2}=\frac{2.5}{r} t$      $...(2)$

For $C:$         $	heta+\pi=\frac{2}{r} t$       $...(3)$

Dividing $(2)$ by $(3),$ we get $	heta=-3 \pi$

 Thus, distance moved by $\mathrm{B}, 	heta_{B}=-3 \pi+\frac{\pi}{2}=-2.5 \pi$

Distance moved by $\mathrm{C}, 	heta_{C}=-3 \pi+\pi=-2 \pi$

$	heta_{B}: 	heta_{C}=5: 4$

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