Three persons work independently on a problem. If the respective probabilities that they will solve it are $\frac{{1}}{{3}} , \frac{{1}}{{4}}$ and $\frac{{1}}{{5}}$, then the probability that none can solve it
$\frac{2}{5}$
$\frac{3}{5}$
$\frac{1}{3}$
None of these
Cards are drawn one by one without replacement from a pack of $52$ cards. The probability that $10$ cards will precede the first ace is
The probability of a sure event is
A die is thrown, find the probability of following events: A number less than or equal to one will appear,
The probability of $A, B, C$ solving a problem are $\frac{1}{3},\,\frac{2}{7},\,\frac{3}{8}$ respectively. If all the three try to solve the problem simultaneously, the probability that exactly one of them will solve it, is
In a simultaneous throw of three coins, what is the probability of getting at least $2$ tails