Three plates of common surface area $A$ are connected as shown. The effective capacitance will be
Three plates of common surface area $A$ are connected as shown. The effective capacitance will be
- A
$\frac{{{\varepsilon _0}A}}{d}$
- B
$\frac{{{3 \varepsilon _0}A}}{d}$
- C
$\frac{3}{2}\frac{{{\varepsilon _0}A}}{d}$
- D
$\frac{{{2 \varepsilon _0}A}}{d}$
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