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1. Electric Charges and Fields
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Two spherical conductors each of capacity $C$ are charged to potential $V$ and $-V$ . These are then connected by mean of a fine conducting wire. The loss of energy will be
A
zero
B
$\frac {1}{2}CV^2$
C
$CV^2$
D
$2CV^2$
Solution
$\mathrm{V}_{\mathrm{C}}=\frac{\mathrm{CV}-\mathrm{CV}}{\mathrm{C}+\mathrm{C}}=0$
$\Delta \mathrm{H}=\left(\frac{1}{2} \mathrm{CV}^{2}+\frac{1}{2} \mathrm{CV}^{2}\right)-\frac{1}{2}(\mathrm{C}+\mathrm{C})(0)^{2}$
$=\mathrm{CV}^{2}$
Standard 12
Physics
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