Gujarati
Hindi
1. Electric Charges and Fields
normal

Two spherical conductors each of capacity $C$ are charged to potential $V$ and $-V$ . These are then connected by mean of a fine conducting wire. The loss of energy will be

A

zero

B

$\frac {1}{2}CV^2$

C

$CV^2$

D

$2CV^2$

Solution

$\mathrm{V}_{\mathrm{C}}=\frac{\mathrm{CV}-\mathrm{CV}}{\mathrm{C}+\mathrm{C}}=0$

$\Delta \mathrm{H}=\left(\frac{1}{2} \mathrm{CV}^{2}+\frac{1}{2} \mathrm{CV}^{2}\right)-\frac{1}{2}(\mathrm{C}+\mathrm{C})(0)^{2}$

$=\mathrm{CV}^{2}$

Standard 12
Physics

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