- Home
- Standard 11
- Physics
10-2.Transmission of Heat
medium
Three rods of the same dimension have thermal conductivities $3K$ , $2K$ and $K$ . They are arranged as shown in fig. Given below, with their ends at $100^oC, 50^oC $and $20^oC$. The temperature of their junction is ......... $^oC$

A
$60$
B
$70$
C
$50$
D
$35$
Solution

(b) Let the temperature of junction be $\theta$ then according to following figure.
$H = H_1 + H_2$
==> $\frac{{3K \times A \times (100 – \theta )}}{l} = \frac{{2KA(\theta – 50)}}{l} + \frac{{KA(\theta – 20)}}{l}$
==> $300 -3\theta = 3\theta -120 $
==> $\theta$ $= 70°C$
Standard 11
Physics
Similar Questions
medium