Time period of a simple pendulum will be double, if we
Decrease the length 2 times
Decrease the length 4 times
Increase the length 2 times
Increase the length 4 times
(d)$T \propto \sqrt l $
If the time period of a two meter long simple pendulum is $2\, s$, the acceleration due to gravity at the place where pendulum is executing $S.H.M.$ is
A simple pendulum of length $ l$ has a brass bob attached at its lower end. Its period is $T$. If a steel bob of same size, having density $ x$ times that of brass, replaces the brass bob and its length is changed so that period becomes $2T$, then new length is
Identify the correct statement
A simple pendulum with length $100\,cm$ and bob of mass $250\,g$ is executing S.H.M. of amplitude $10\,cm$. The maximum tension in the string is found to be $\frac{x}{40}\,N$. The value of $x$ is $……….$.
What happens to the time period of a simple pendulum when it is taken to moon's surface from earth's surface ?
Confusing about what to choose? Our team will schedule a demo shortly.