Time period of pendulum, on a satellite orbiting earth, is

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13.Oscillations

easy

Time period of pendulum, on a satellite orbiting the earth, is

$1 / \pi$

zero

$\pi$

infinity

(AIIMS-2016)

Solution

(d)

As we know, $T \alpha \frac{1}{\sqrt{ g }}$
On a artificial satellite, orbiting the earth, neg gravity is zero. As,
$\Rightarrow \quad g =0 \Rightarrow T \rightarrow \infty$

Standard 11

Physics

The period of small oscillation of a simple pendulum is $T$. The ratio of density of liquid to the density of material of the bob is $\rho \left( {\rho < 1} \right)$.When immersed in the liquid, the time period of small oscillation will now be

hard

A simple pendulum is set up in a trolley which moves to the right with an acceleration a on a horizontal plane. Then the thread of the pendulum in the mean position makes an angle $\theta $ with the vertical

medium

Column $I$ gives a list of possible set of parameters measured in some experiments. The variations of the parameters in the form of graphs are shown in Column $II$. Match the set of parameters given in Column $I$ with the graph given in Column $II$. Indicate your answer by darkening the appropriate bubbles of the $4 \times 4$ matrix given in the $ORS$.

Column $I$ Column $II$

$(A)$ Potential energy of a simple pendulum (y axis) as a function of displacement ( $\mathrm{x}$ axis) $Image$

$(B)$ Displacement (y axis) as a function of time (x axis) for a one dimensional motion at zero or constant acceleration when the body is moving along the positive $\mathrm{x}$-direction $Image$

$(C)$ Range of a projectile (y axis) as a function of its velocity ( $\mathrm{x}$ axis) when projected at a fixed angle $Image$

$(D)$ The square of the time period (y axis) of a simple pendulum as a function of its length ( $\mathrm{x}$ axis) $Image$

normal

(IIT-2008)

The length of a simple pendulum is increased by $1\%$. Its time period will