Gujarati
13.Oscillations
easy

The length of a simple pendulum is increased by $1\%$. Its time period will

A

Increase by $1\%$

B

Increase by $0.5\%$

C

Decrease by $0.5\%$

D

Increase by $2\%$

Solution

(b) $T \propto \sqrt l $

==> $\frac{{\Delta T}}{T} = \frac{1}{2}\frac{{\Delta l}}{l} = \frac{1}{2} \times 1\% = 0.5\% $

Standard 11
Physics

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