Time taken by an object falling from rest to cover height of {h₁} and {h₂} is respectively {t₁

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2.Motion in Straight Line

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Time taken by an object falling from rest to cover the height of ${h_1}$ and ${h_2}$ is respectively ${t_1}$ and ${t_2}$ then the ratio of ${t_1}$ to ${t_2}$ is

A

${h_1}\;:\;{h_2}$

B

$\sqrt {{h_1}} \;:\;\sqrt {{h_2}} $

C

${h_1}\;:\;2{h_2}$

D

$2h_1 : h_2$

Solution

(b)$t = \sqrt {\frac{{2h}}{g}} \Rightarrow \frac{{{t_1}}}{{{t_2}}} = \sqrt {\frac{{{h_1}}}{{{h_2}}}} $

Standard 11

Physics

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