Gujarati
2.Motion in Straight Line
easy

किसी वस्तु को ${h_1}$ तथा ${h_2}$ ऊँचाईयों तक गिरने में लगने वाले समय क्रमश: ${t_1}$ व ${t_2}$ हों तो ${t_1}:{t_2}$ होगा

A

${h_1}\;:\;{h_2}$

B

$\sqrt {{h_1}} \;:\;\sqrt {{h_2}} $

C

${h_1}\;:\;2{h_2}$

D

$2h_1 : h_2$

Solution

(b)$t = \sqrt {\frac{{2h}}{g}} \Rightarrow \frac{{{t_1}}}{{{t_2}}} = \sqrt {\frac{{{h_1}}}{{{h_2}}}} $

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.