Two balls are thrown simultaneously from grou | vedclass

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Question

(a)

$5 \sqrt{3}=\frac{(10)^2 \sin 2 	heta}{g} 	ext { or } \sin 2 	heta=\frac{\sqrt{3}}{2}$

$	herefore 2 	heta=60^{\circ} 	ext { or } 	het

Vedclass · Accepted Answer

$(\sqrt{3}-1)\,s$

Vedclass · Answer

(a)

$5 \sqrt{3}=\frac{(10)^2 \sin 2 	heta}{g} 	ext { or } \sin 2 	heta=\frac{\sqrt{3}}{2}$

$	herefore 2 	heta=60^{\circ} 	ext { or } 	heta=30^{\circ}$

Two different angles of projection are therefore, $	heta$ and $\left(90^{\circ}-	hetaight)$ or $30^{\circ}$ and $60^{\circ}$.

Two different angles of projection are therefore, $	heta$ and $\left(90^{\circ}-	hetaight)$ or $30^{\circ}$ and $60^{\circ}$.

$T_1=\frac{2 u \sin 30^{\circ}}{g}=1\,s$

$T_2=2 \frac{u \sin 60^{\circ}}{g}=\sqrt{3}\,s$

$\Delta t=T_2-T_1=(\sqrt{3}-1)\,s$

Two balls are thrown simultaneously from ground with same velocity of $10\,m / s$ but different angles of projection with horizontal. Both balls fall at same distance $5 \sqrt{3}\,m$ from point of projection. What is the time interval between balls striking the ground?

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