There are two points P and Q on a projectile with velocities v_P and v_Q respectively such that v_P

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3-2.Motion in Plane

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There are two points $P$ and $Q$ on a projectile with velocities $v_P$ and $v_Q$ respectively such that $v_P$ is perpendicular to $v_Q$ and $\alpha$ is the angle that $v_P$ makes with horizontal at point $P$. Find the correct option

A

$\tan \,\alpha \, = \,\frac{{{v_Q}}}{{{v_P}}}$

B

$\cos \,\alpha \, = \,\frac{{{v_Q}}}{{{v_P}}}$

C

$\sec \,\alpha \, = \,\frac{{{v_Q}}}{{{v_P}}}$

D

$\cot \,\alpha \, = \,\frac{{{v_Q}}}{{{v_P}}}$

Solution

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Standard 11

Physics

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