Two blocks A and B of masses 1,,kg and 2,,kg are conne

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5.Work, Energy, Power and Collision

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Two blocks $A$ and $B$ of masses $1\,\,kg$ and $2\,\,kg$ are connected together by a spring and are resting on a horizontal surface. The blocks are pulled apart so as to stretch the spring and then released. The ratio of $K.E.s$ of both the blocks is

A

$1$

B

$2$

C

$0.5$

D

$0.25$

Solution

From consv. of momentum, $p_1 = p_2$ and $KE = \frac {P^2}{2m}$

$\frac{{K{E_1}}}{{K{E_2}}}\, = \,\frac{{P_1^2}}{{P_2^2}}\, \times \,\frac{{{m_2}}}{{{m_1}}}\, = \,\frac{2}{1}\, = 2$

Standard 11

Physics

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