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5.Work, Energy, Power and Collision
normal
A particle of mass $M$ is moving in a horizontal circle ofradius $R$ with uniform speed $v$. When it moves from one point to a diametrically opposite point, its
A
kinetic energy change by $M v^{2} / 4$
B
momentum does not change
C
momentum change by $2 M v$
D
kinetic energy changes by $M v^{2}$
Solution
On the diametrically opposite points, the velocities have same magnitude but opposite directions.
Therefore change in momentum is $M v-(-M v)=2 M v$
Standard 11
Physics
