Two blocks ( m =0.5, kg and M =4.5, kg ) are arranged on a horizontal frictionless table as shown in

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4-2.Friction

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Two blocks $( m =0.5\, kg$ and $M =4.5\, kg$ ) are arranged on a horizontal frictionless table as shown in figure. The coefficient of static friction between the two blocks is $\frac{3}{7} .$ Then the maximum horizontal force that can be applied on the larger block so that the blocks move together is ......... $N.$ (Round off to the Nearest Integer) [Take g as $9.8\, ms ^{-2}$ ]

A

$35$

B

$24$

C

$21$

D

$27$

(JEE MAIN-2021)

Solution

$a_{\max }=\mu g=\frac{3}{7} \times 9.8$

$F =( M + m ) a _{\max }=5 a _{\max }$

$=21$ Newton

Standard 11

Physics

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