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4-1.Newton's Laws of Motion
medium
Two blocks of mass $2 \,kg$ and $4 kg$ are accelerated with same acceleration by a force $10 \,N$ as shown in figure on a smooth horizontal surface. Then the spring force between the two blocks will be .......... $N$ (spring is massless)
A$5$
B$10$
C$\frac{10}{3}$
D$\frac{5}{3}$
Solution
(c)
The correct answer is $C$.
Given,
masses $=2\,kg , 4\, kg$
$f =10\,N$
So,
Force $(f)=(2+4) a$
or,
$a=\frac{f}{6}=\frac{10}{6} m / s ^2$
Let the force of spring is $T$
so,
$T=2 a=2 \times \frac{10}{6}$
$=\frac{10}{3}\,N$
Thus, the spring force between the two blocks will be $\frac{10}{3}\,N$
The correct answer is $C$.
Given,
masses $=2\,kg , 4\, kg$
$f =10\,N$
So,
Force $(f)=(2+4) a$
or,
$a=\frac{f}{6}=\frac{10}{6} m / s ^2$
Let the force of spring is $T$
so,
$T=2 a=2 \times \frac{10}{6}$
$=\frac{10}{3}\,N$
Thus, the spring force between the two blocks will be $\frac{10}{3}\,N$
Standard 11
Physics