Two bodies are projected with the same veloci | vedclass

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Question

(b) As $H = \frac{{{u^2}{{\sin }^2}	heta }}{{2g}}$

$&rArr;$  $\frac{{{H_1}}}{{{H_2}}} = \frac{{{{\sin }^2}{	heta _1}}}{{\sin {	heta _2}}} =

Vedclass · Accepted Answer

$1:3$

Vedclass · Answer

(b) As $H = \frac{{{u^2}{{\sin }^2}	heta }}{{2g}}$

$&rArr;$  $\frac{{{H_1}}}{{{H_2}}} = \frac{{{{\sin }^2}{	heta _1}}}{{\sin {	heta _2}}} = \frac{{{{\sin }^2}30^\circ }}{{{{\sin }^2}60}}$= $\frac{{1/4}}{{3/4}} = \frac{1}{3}$

Two bodies are projected with the same velocity. If one is projected at an angle of ${30^o}$ and the other at an angle of ${60^o}$ to the horizontal, the ratio of the maximum heights reached is

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