Two bodies of different masses {mₐ} and {mₓ} are dropped from two different heights a and b . ra

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2.Motion in Straight Line

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Two bodies of different masses ${m_a}$ and ${m_b}$ are dropped from two different heights $a$ and $b$. The ratio of the time taken by the two to cover these distances are

A

$a:b$

B

$b:a$

C

$\sqrt a :\sqrt b $

D

${a^2}:{b^2}$

Solution

(c) $h = \frac{1}{2}g{t^2} \Rightarrow t = \sqrt {2h/g} $

${t_a} = \sqrt {\frac{{2a}}{g}} \,\,{\rm{and}}\;\,{t_b} = \sqrt {\frac{{2b}}{g}} \Rightarrow \frac{{{t_a}}}{{{t_b}}} = \sqrt {\frac{a}{b}} $

Standard 11

Physics

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