Two charges each equal to 2,μ C are 0.5,m apart. If both of them exist inside vacuum, then force be

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1. Electric Charges and Fields

easy

Two charges each equal to $2\,\mu C$ are $0.5\,m$ apart. If both of them exist inside vacuum, then the force between them is.......$N$

$1.89$

$2.44$

$0.14$

$3.14$

Solution

(c) By using $F = 9 \times {10^9}.\frac{{{Q^2}}}{{{r^2}}}$
$==>$ $F = 9 \times {10^9}.\frac{{{{(2 \times {{10}^{ – 6}})}^2}}}{{{{(0.5)}^2}}} = 0.144\,N$

Standard 12

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