Two equal positive point charges are separated by a distance 2 a . distance of a point from centre o

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1. Electric Charges and Fields

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Two equal positive point charges are separated by a distance $2 a$. The distance of a point from the centre of the line joining two charges on the equatorial line (perpendicular bisector) at which force experienced by a test charge $q_0$ becomes maximum is $\frac{a}{\sqrt{x}}$. The value of $x$ is $................$

A

$4$

B

$2$

C

$8$

D

$10$

(JEE MAIN-2023)

Solution

$F=\frac{2 K q q_0 x}{\left(x^2+a^2\right)^{3 / 2}}$

For $F$ to be maximum

$\frac{ d F}{ d x}=0$

$x=\frac{a}{\sqrt{2}}$

Standard 12

Physics

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