Two charges placed in air repel each other by a force of {10^{ - 4}},N . When oil is introduced betw

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1. Electric Charges and Fields

easy

Two charges placed in air repel each other by a force of ${10^{ - 4}}\,N$. When oil is introduced between the charges, the force becomes $2.5 \times {10^{ - 5}}\,N$. The dielectric constant of oil is

A

$2.5$

B

$0.25$

C

$2$

D

$4$

Solution

(d) By using $K = \frac{{{F_a}}}{{{F_m}}} \Rightarrow K = \frac{{{{10}^{ – 4}}}}{{2.5 \times {{10}^{ – 5}}}} = 4$

Standard 12

Physics

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