Two cubical blocks identical in dimensions float in water in such a way that 1 st block floats with

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9-1.Fluid Mechanics

medium

Two cubical blocks identical in dimensions float in water in such a way that $1$ st block floats with half part immersed in water and second block floats with $3 / 4$ of its volume inside the water. The ratio of densities of blocks is ..........

$2: 3$

$3: 4$

$1: 3$

$1: 4$

Solution

(a)

$\frac{3}{4} V \times \rho_2 \times g=\frac{1}{2} V \times \rho_1 \times g$ $\left\{\begin{array}{l}V=\text { Volume of block } \\ \rho_1=\text { density of liquid } 1 \\ \rho_2=\text { density of liquid } 2\end{array}\right.$

$\Rightarrow \frac{\rho_2}{\rho_1}=\frac{2}{3}$

Standard 11

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Two cubical blocks identical in dimensions float in water in such a way that $1$ st block floats with half part immersed in water and second block floats with $3 / 4$ of its volume inside the water. The ratio of densities of blocks is ..........

Solution

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