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14.Probability
easy
Two dice are thrown simultaneously. The probability of getting the sum $2$ or $8$ or $12$ is
A
$\frac{5}{{18}}$
B
$\frac{7}{{36}}$
C
$\frac{7}{{18}}$
D
$\frac{5}{{36}}$
Solution
(b) The sum $2$ can be found in one way $i.e.$ $(1,\,\,1)$
The sum $8$ can be found in five ways
$i.e.$ $(6,\,\,2),$ $(6,\,\,2),\,(5,\,\,3),$ $\,(4,\,\,4),\,(3,\,\,5),\,(2,\,\,6)$.
Similarly the sum twelve can be found in one way $i.e.,$ $(6,\,\,6).$
Hence required probability $ = \frac{7}{{36}}.$
Standard 11
Mathematics
