Two dice are thrown simultaneously. The proba | vedclass

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Question

(b) The sum $2$ can be found in one way $i.e.$ $(1,\,\,1)$

The sum $8$ can be found in five ways

$i.e.$ $(6,\,\,2),$ $(6,\,\,2),\,(5,\,\,3),$ $\

Vedclass · Accepted Answer

$\frac{7}{{36}}$

Vedclass · Answer

(b) The sum $2$ can be found in one way $i.e.$ $(1,\,\,1)$

The sum $8$ can be found in five ways

$i.e.$ $(6,\,\,2),$ $(6,\,\,2),\,(5,\,\,3),$ $\,(4,\,\,4),\,(3,\,\,5),\,(2,\,\,6)$.

Similarly the sum twelve can be found in one way $i.e.,$ $(6,\,\,6).$

Hence required probability $ = \frac{7}{{36}}.$

Two dice are thrown simultaneously. The probability of getting the sum $2$ or $8$ or $12$ is

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