Two exactly similar wires of steel and copper are stretched by equal forces. If the difference in their elongations is $0.5$ cm, the elongation $(l)$ of each wire is ${Y_s}({\rm{steel}}) = 2.0 \times {10^{11}}\,N/{m^2}$${Y_c}({\rm{copper}}) = 1.2 \times {10^{11}}\,N/{m^2}$
Two exactly similar wires of steel and copper are stretched by equal forces. If the difference in their elongations is $0.5$ cm, the elongation $(l)$ of each wire is ${Y_s}({\rm{steel}}) = 2.0 \times {10^{11}}\,N/{m^2}$${Y_c}({\rm{copper}}) = 1.2 \times {10^{11}}\,N/{m^2}$
- A
${l_s} = 0.75\,cm,\;{l_c} = 1.25\,cm$
- B
${l_s} = 1.25\,cm,\;{l_c} = 0.75\,cm$
- C
${l_s} = 0.25\,cm,\;{l_c} = 0.75\,cm$
- D
${l_s} = 0.75\,cm,\;{l_c} = 0.25\,cm$
Similar Questions
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- [JEE MAIN 2024]
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