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Question

(d) Initial condition is 

So, initial value of force between spheres is $F=k q^2 / r^2$.

When another identical and uncharged sphere $C$ is

Vedclass · Accepted Answer

$\frac{3 F}{8}$

Vedclass · Answer

(d) Initial condition is 

So, initial value of force between spheres is $F=k q^2 / r^2$.

When another identical and uncharged sphere $C$ is touched to $A$, charge on each of $A$ and $C$ will be $\frac{q}{2}$.

When $C$ is touched with $B$, then charge on each of them will be mean value of total charge.

So, charge on $B=$ charge on $C$

$=\frac{q+\frac{q}{2}}{2}=\frac{3 q}{4}$

Now, the final condition is

So, final value of force between spheres is

$\frac{F^{\prime}-k q_1 \cdot q_2}{r^2}$

$=\frac{k \frac{9}{2} 	imes \frac{3 q}{4}}{r^2}=\frac{3}{8} \frac{k q^2}{r^2}$

or $F^{\prime}=\frac{3}{8} F$

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