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1. Electric Charges and Fields
easy
Two identical pendulum $A$ and $B$ are suspended from the same point. The bobs are given positive charges, with $A$ having more charge than $B$ . They diverge and reach at equilibrium, with $A$ and $B$ making angles $\theta _1$ and $\theta _2$ with the vertical respectively, Then
A
$\theta _1 = \theta _2$
B
$\theta _1 > \theta _2$
C
$\theta _1 < \theta _2$
D
Tension in $A$ is smaller than in $B$
Solution
According the conditions of coulomb forces, both the balls repel each other with a force
$\mathrm{F}_{\mathrm{e}}=\frac{\mathrm{q}_{1} \mathrm{q}_{2}}{4 \pi \varepsilon_{0} \mathrm{r}}$
Thus, forces $\mathrm{F}_{\mathrm{e}}$ and $\mathrm{mg}$ are identical on both the balls, hence in static equilibrium
$\theta_{1}=\theta_{2}.$
Standard 12
Physics